dbcrisp671 dbcrisp671
  • 26-04-2018
  • Mathematics
contestada

if a normal distribution has a mean of 132 and a standard devistion of 20, what is the value that has a z score of 1.8?

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MsEHolt MsEHolt
  • 06-05-2018
The value would be 168.

The formula for a z-score is
z = (X-μ)/σ

Using our information, we have 
1.8 = (X-132)/20

Multiply both sides by 20:
1.8(20) = ((X-132)/20)*20
36 = X-132

Add 132 to both sides:
36+132 = X-132+132
168 = X
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tylittle85p69p8h tylittle85p69p8h
  • 15-11-2018

for people that have 3.6 instead of 1.8 you do the same thing,

3.6=(x-132)/20 it would be a.204 <---- apex.

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