briannaml briannaml
  • 25-04-2018
  • Mathematics
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PLZ HELP ASAP RIGHT TRIANGLES

PLZ HELP ASAP RIGHT TRIANGLES class=

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IsrarAwan
IsrarAwan IsrarAwan
  • 25-04-2018
The correct  answer is: AC = [tex]9 \sqrt{3} [/tex]

Explanation:
Since
[tex]sin(\theta) = perpendicular/hypotenuse [/tex]

Here
[tex]\theta[/tex] = 60°

Perpendicular = x = ?
Hypotenuse = AB = 18

So
Perpendicular = A = sin(60)*18
x = AC = [tex]9 \sqrt{3} [/tex]
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