jakescameron23p4qs5a
jakescameron23p4qs5a
26-02-2018
Mathematics
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Evaluate12P3 and10C4
Respuesta :
estherng0722
estherng0722
26-02-2018
[tex] 12P3 = \frac{12!}{(12-3)!} [/tex]
=1320
[tex]10C4 = \frac{10!}{4!(10-4)!} [/tex]
= 210
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