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A 40-w lightbulb connected to a 120-v source experiences a voltage surge that produces 132 v for a moment. by what percentage does its power output increase? assume its resistance does not change.a 40-w lightbulb connected to a 120-v source experiences a voltage surge that produces 132 v for a moment. by what percentage does its power output increase? assume its resistance does not change.

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qq2480816826
R=U^2/P=120*120/40=360 ohm
P2=U2^2/R=132*132/360=48.4 w
power increase ratio (48.4-40)/40=21%
pstnonsonjoku

From the calculation, the percentage increase in the power is 21%.

What is power?

The power of a circuit is obtained from;

P = V^2/R

Now;

P = 40 W

V = 120 V

R =V^2/P

R =(120)^2/40

R =360 ohm

If the voltage is increased to 132 V, the power becomes;

P= (132)^2/ 360

P = 48.4 W

The change in the power = 48.4 W - 0 W/40 W * 100/1

= 21%

Learn more about power in a circuit:https://brainly.com/question/2933971?

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