Respuesta :
1.0x10^3 newtons of force
1.0x10^2 kilograms of weight (assuming local gravity of 9.8 m/s^2)
I will assume that the external pressure is 1 atmosphere (101325 Pascals) since it wasn't specified in the problem. So let's simply multiply the area of the suction cup by the pressure and see what we get:
101325 P * 0.01 m^2
= 101325 kg/(m*s^2) * 0.01 m^2
= 1013.25 kg*m/s^2
= 1013.25 N
So the suction cup can support 1013.25 Newtons of force. Assuming the local gravitational acceleration is 9.8 m/s^2, let's see how many kilograms that is
1013.25 N / 9.8 m/s^2
= 1013.25 kg*m/s^2 / 9.8 m/s^2
= 103.3928571 kg
Rounding to 2 significant figures gives 1.0x10^3 newtons, or 1.0x10^2 kilograms.