sharonnnnnnnb3978 sharonnnnnnnb3978

23-10-2017
Physics

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A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the lightbulb?

Respuesta :

23-10-2017

Current = voltage / resistance

= 110 v / 285 Ω

= 0.386 Ampere (rounded)

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