WilliamU10 WilliamU10
  • 24-05-2024
  • Mathematics
contestada

Y starting at 82 and multiplied by factor of 3 a each time increases by 1

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clarencearaza98 clarencearaza98
  • 24-05-2024

Answer:

Starting with the number 82 and multiplying by a factor of 3 each time, the sequence increases by 1 incrementally can be represented as:

82 * 3^0 = 82

82 * 3^1 = 246

246 * 3^2 = 738

738 * 3^3 = 2214

2214 * 3^4 = 6642

Therefore, the sequence starting at 82 and multiplying by a factor of 3 each time, increasing by 1 after each multiplication, follows the progression: 82, 246, 738, 2214, 6642.

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