Respuesta :

[tex]\bf 60=10\sqrt{y-3}\implies \cfrac{60}{10}=\sqrt{y-3}\implies 6=\sqrt{y-3} \\\\\\ \textit{now, we simply raise both at }^2 \\\\\\ (6)^2=(\sqrt{y-3})^2\implies 36=y-3\implies 36+3=y\implies 39=y[/tex]

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