Formula
[tex]f(x)=a(x-p)^2+q[/tex] , V = (p,q)
[tex]f(x)=2x^2+6x-8\\\\\ f(x)=ax^2+bx+c\\\\ a=2 \ , \ b=6 \ , \ c=-8 \\\\ p=\frac{-b}{2a}=\frac{-6}{\not2* 2}=-\frac{3}{2}\\\\q=\frac{-\Delta}{4a}=\frac{-(b^2-4ac)}{4a}=\frac{-[6^2-4*2*(-8)]}{4*2}=\frac{-100}{8}=-\frac{25}{2}[/tex]
[tex]f(x)=2(x-(-\frac{3}{2})^2+(-\frac{25}{2})[/tex]
Answer
[tex]f(x)=2(x+\frac{3}{2})^2-\frac{25}{2}\\\\ or\\\\ f(x)=2(x+1.5)^2-12.5[/tex]
V = (p,q) = (-1.5 ; -12.5)
