Respuesta :

dexteright02
Data:
[tex]A_{base} = 4 \frac{3}{4} = \frac{4*4+3}{4} = \frac{16+3}{4} \to A_{base} = \frac{19}{4}[/tex]

[tex]h (height) = 2 \frac{1}{3} = \frac{3*2+1}{3} = \frac{6+1}{3} \to h (height) = \frac{7}{3} [/tex]
[tex]v (volume) = ?[/tex]

Formula: [tex]V = A_{b}*h [/tex]

Solving:
[tex]V = A_{b}*h [/tex]
[tex]V = \frac{19}{4} * \frac{7}{3} [/tex]
[tex]V = \frac{133}{12} [/tex]
[tex]V = 11.08333....[/tex]
[tex]\boxed{\boxed{V \approx 11.08}}\end{array}}\qquad\quad\checkmark[/tex]

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