To evaluate the expression
[tex]r=1\text{ , n=3 , t= 12 , v = 0 , w= }\frac{-1}{2}[/tex]
[tex](9)6r+2n\text{ = 6(1)+2(3)=6+6= 12}[/tex][tex](10)\text{ w(n-r) = }\frac{-1}{2}(3-1)=\frac{-1}{2}(2)=-1[/tex][tex](13)(4n)^2=(4x3)^2=12^2=144[/tex][tex](15)\text{ 2(3r+w) = 2(3 x 1+-}\frac{1}{2})=2(3-\frac{1}{2})\text{ = 2(}\frac{5}{2})=5[/tex][tex]undefined[/tex]
