We are given the following sequence
[tex]c(n)=-6(-\frac{1}{3})^{n-1}[/tex]We are asked to find the 2nd term of the above sequence
Let us substitute n = 2 into the given sequence
[tex]\begin{gathered} c(2)=-6(-\frac{1}{3})^{2-1} \\ c(2)=-6(-\frac{1}{3})^1 \\ c(2)=6\cdot\frac{1}{3} \\ c(2)=2 \end{gathered}[/tex]Therefore, the 2nd term of the given sequence is 2
