Given that y= x^2+x+12, to write the expression in an intercept form we need to factorize the expression.
[tex]y=-x^2+x+12[/tex]The intercept form is of the format
[tex]y=a(x\pm p)(x\pm q)_{}[/tex]This is obtained by factoring the quadratic equation above
[tex]\begin{gathered} y=-x^2+4x-3x+12 \\ y=-x(x-4)-3(x-4) \\ y=(x-4)(-x-3) \\ y=-1(x+3)(x-4) \end{gathered}[/tex]Hence, the intercept form of the equation is y= -1 (x + 3) ( x - 4 )
