Given
[tex]\begin{gathered} \text{Ate 4}\frac{5}{12}\text{Plates of chocolate cupcakes} \\ \text{And} \\ \text{Ate 2}\frac{1}{3}\text{plates of cherry} \end{gathered}[/tex]
We are to add them together to know the total
[tex]4\frac{5}{12}+2\frac{1}{3}=6\frac{5+4}{12}=6\frac{9}{12}=6\frac{3}{4}[/tex]
The final answer
[tex]6\frac{3}{4}[/tex]
