[tex]4(2x-1\text{ ) < 2(4x-3)}[/tex][tex]8x\text{ -4 < 8x -6}[/tex][tex]8x\text{ - 8x <-6 +4}[/tex][tex]\begin{gathered} so\text{ } \\ 8x\text{ - 8x = 0} \\ \text{therefore} \\ 0\text{ < -2} \\ \text{could it be the question is } \\ 4(2x-1)<4x\text{ - 1?} \\ \text{because the original questions makes little sense} \end{gathered}[/tex]
