Respuesta :

Answer:

51.92 m

Explanation:

Given

  • angle at which it is launched (α) = 30°
  • initial velocity (v₀) = 31.9 m/s

Formula

  • Range (R) = [tex]\frac{v_{0}^{2} sin2\alpha }{g}[/tex]

Solving for R

  • R = (31.9)² x sin2(30°) / 9.8
  • R = 1017.61 x sin60° / 9.8
  • R = 1017.61 / 19.6 [sin 60° = 1/2]
  • R = 51.92 m

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