ahmdsuf204033 ahmdsuf204033
  • 23-04-2022
  • Mathematics
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cos^2-sin^2=1/3
so what is cos^4-sin^4

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Аноним Аноним
  • 23-04-2022

Step-by-step explanation:

[tex]cos ^{2} x - \sin ^{2} x = \frac{1}{3} [/tex]

[tex] \frac{(cos ^{2}x - \sin ^{2} x)(cos ^{2}x + \sin ^{2} x)}{(cos ^{2}x + \sin ^{2} x)} = \frac{1}{3} [/tex]

[tex] \frac{(cos ^{4}x - \sin ^{4} x)}{1} = \frac{1}{3} [/tex]

as cos²x+sin²x=1

Hence

cos⁴x-sin⁴x=1/3

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