AlexisLee
contestada

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s2, what is the radius of the circle?

0.60 m
1.2 m
0.36 m
0.84 m

Respuesta :

grandpianograce

I googled it and I think the answer is 0.60m


good luck!

carlosego

By definition, the centripetal acceleration is given by:

[tex] a = \frac{v^2}{r}
[/tex]

Where,

v: tangential speed

r: radius of the circular path

Clearing the radio we have:

[tex] r = \frac{v^2}{a}
[/tex]

Substituting values we have:

[tex] r =\frac{0.51 ^ 2}{0.43}

r = 0.6 m
[/tex]

Therefore, the radius of the circular path is equal to 0.60 meters.

Answer:

The radius of the circle is:

0.60 m

option1