answer:
[tex]\sf 2x^2 + 9x +10[/tex]
solving steps:
[tex]\sf{area \ of \ triangle = \frac{1}{2} * base *height }[/tex]
[tex]\sf{Here \ the \ base \ is \ (2x+5) \ and \ height \ is \ (2x+4)[/tex]
[tex]\sf\hookrightarrow \frac{1}{2} * (2x +5)*(2x+4)}[/tex]
[tex]\sf \hookrightarrow { \frac{1}{2} *(4x^2 + 8x + 10x + 20)[/tex]
[tex]\sf \hookrightarrow { \frac{1}{2} *(4x^2 + 18x + 20)[/tex]
[tex]\sf \hookrightarrow 2x^2 + 9x +10[/tex]
