Answer:
Step-by-step explanation:
[tex]a) x_{1+1}=\dfrac{(x_{1})^{3}-5}{10}\\\\x_{2}=\dfrac{(-1)^{3}-5}{10}=\dfrac{-1-5}{10}=\dfrac{-6}{10}= - 0.6\\\\\\ii) x_{2+1}=\dfrac{(x_{2})^{3}-5}{10}\\\\x_{3}=\dfrac{(-0.6)^{3}-5}{10}=\dfrac{-0.216-5}{10}=\dfrac{-5.216}{10}= - 0.5216\\\\\\[/tex]
