Respuesta :

mahrezrokaya

Answer:

(2x-4) (x+5)=0

2x(x+5) -4(x+5)=0

2x^2+10x-4x-20=0

2x^2+6x-20=0

x^2+3x-10=0 ( Taking common of 2 )

x^2+(5-2)x-10=0 • (3=(5-2)x)

x^2+5x-2x-10=0

x(x+5)-2(x-5) =0 • Taking common

(x+5)(x-2) =0

so x=-5 or x=2.

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