ZNZACFSVSZJATYFASV
ZNZACFSVSZJATYFASV ZNZACFSVSZJATYFASV
  • 25-07-2021
  • Mathematics
contestada

I need help with that, if you can, plz. I ty it I think is a not sure

I need help with that if you can plz I ty it I think is a not sure class=

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 25-07-2021

Answer:

-5≤x <1

Step-by-step explanation:

sqrt( x+5) / sqrt(1-x)

The numerator must be greater than zero since it is a square root

sqrt(x+5) ≥0

Square each side

x+5≥0

x≥-5

The denominator must be greater than zero (the denominator cannot be zero)

sqrt(1-x)> 0

Square each side

1-x > 0

1>x

Putting these together

-5≤x <1

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