Answer: [tex]\displaystyle\ \large \boldsymbol{ 2t^2+5t+2= {(2t+1) (t+2)}}[/tex]
Step-by-step explanation:
[tex]\displaystyle\ \large \boldsymbol{} 2t^2+5t+2=0 \\\\2t^2+\underbrace{4t+t}_{5t}+2=0 \\\\ (2t^2+4t)+(t+2)=0 \\\\ 2t(\underline{t+2})+(\underline{t+2})=0 \\\\ \boxed{(2t+1) (t+2)=0 }[/tex]
