Ocean waves of wavelength 22 m are moving directly toward a concrete barrier wall at 4.6 m/s . The waves reflect from the wall, and the incoming and reflected waves overlap to make a lovely standing wave with an antinode at the wall. (Such waves are a common occurrence in certain places.) A kayaker is bobbing up and down with the water at the first antinode out from the wall.

Required:
a. How far from the wall is she?
b. What is the period of her up-and-down motion?

Question

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Respuesta :

okpalawalter8 okpalawalter8 · Answer 1 · 2021-06-24T04:34:50+02:00

Answer:

a) [tex]d=11m[/tex]

b) [tex]T=4.68s[/tex]

Explanation:

From the question we are told that:

Wavelength [tex]\lambda=22m[/tex]

Velocity [tex]v=4.6m/s[/tex]

a)

Generally the equation for distance between her and the wall d is mathematically given by

Since

The First Anti node distance is [tex]\frac{\lambda}{2}[/tex]

Therefore

[tex]d= \frac{\22}{2}[/tex]

[tex]d=11m[/tex]

b)

Generally the equation for her up-and-down motion is mathematically given by

[tex]T=\frac{22}{4.7}[/tex]

[tex]T=4.68s[/tex]