Answer:
[tex]\frac{\sqrt{69}}{\sqrt{94}}[/tex]
Step-by-step explanation:
Cos (G) is Adjacent side over Hypotenuse.
So, first you have to find the missing (adjacent) side using the Pythagorean theorem of [tex]a^{2} +b^{2} =c^{2}[/tex].
so substitute the numbers in the formula to get
[tex]5^{2} +b^{2} = (\sqrt{94})^{2}[/tex]
solve for b.
[tex]25+b^2=94\\b^2=69\\b=\sqrt{69}[/tex]
So adjacent over hypotenuse is [tex]\frac{\sqrt{69}}{\sqrt{94}}[/tex]
