Answer:
30
Step-by-step explanation:
To find the greatest number divisible : find the GCF
[tex]60 = 2 \times 2 \times 3 \times 5 = 2^2 \times 3^1 \times 5^1\\\\90 = 2 \times 3 \times 3 \times 5 = 2^1 \times 3^2 \times 5\\\\120 = 2 \times 2 \times 2 \times 3 \times 5 = 2^3 \times 3^1 \times 5^1[/tex]
[tex]Therefore \ , GCF = 2 \times 3 \times 5 = \ 30[/tex]
Therefore greatest number in which 60, 90 , 120 are divisible = 30
