Respuesta :

abidemiokin

Answer:

θ =  5.6251 + n*2π

Step-by-step explanation:

Given the expression

18cos(10x)+2=10

18cos(10x) = 10 -2

18cos(10x) = 8

cos(10x) = 8/18

cos(10x) = 5/9

10x = arccos(5/9)

10x = 56.251

x = 56.251/10

x = 5.6251

For cos theta

θ=cos^-1a+n*2π

θ = 5.6251 + n*2π