Answer:
The decreasing in concentration occurs after 69.0s
Explanation:
A first order reaction follows the equation:
Ln [A] = -kt + ln[A]₀
Where [A] is the concentration of the reactant after time t
k is rate constant of the reaction
And [A]₀ is the initial concentration of the reactant
Replacing:
Ln 2.45x10⁻²M = -1.80x10⁻²s⁻¹*t + ln8.48x10⁻²
-3.709 = -1.80x10⁻²s⁻¹*t -2.467
-1.2416 = -1.80x10⁻²s⁻¹*t
69.0s = t
The decreasing in concentration occurs after 69.0s
