el4byo3rgirlrac el4byo3rgirlrac
  • 24-11-2016
  • Chemistry
contestada

how many oxygen atoms are in 4.40g of Al2(so4)3?

Respuesta :

scme1702
scme1702 scme1702
  • 26-11-2016
First, we calculate the moles of Al₂(SO₄)₃:

moles = mass / Mr
= 4.4 / (27 x 2 + 3 x (32 + 16 x 4))
= 0.013 mole

Each mole of Al₂(SO₄)₃ contains 12 moles of Oxygen
Moles of oxygen = 12 x 0.013
= 0.156

Each mole of Oxygen contains 6.02 x 10²³ atoms
Atoms of Oxygen = 0.156 x 6.02 x 10²³
= 9.39 x 10²² atoms
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