Respuesta :

bartdrinksmalk
Both [tex]\frac{4}{5}x+1[/tex] and [tex]\frac{4}{5}x-3[/tex] are equal to [tex]y[/tex], so they equal each other:
[tex]\frac{4}{5}x+1=\frac{4}{5}x-3[/tex]
[tex]\rightarrow1=-3[/tex]
But this can't happen.

So there is no solution to the equations.

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