Respuesta :

JcAlmighty
The answer is [tex]x = - \frac{4}{3} [/tex]

[tex] 27^{2x} = 9^{(x-3)} \\ (3^{3} )^{2x} = (3^{2}) ^{(x-3)} \\ \\ (x^{a} )^{b}= x^{a*b} \\  3^{3*2x} =3^{2*(x-3)} \\ 3^{6x} =3^{(2x-6)} [/tex]

Now, logarithm both sides of the equation:
[tex]log(3^{6x} )=log(3^{(2x-6)}) \\ \\ log (x^{a}) =a*log(x) \\ 6x*log(3)=(2x-6)*log(3)[/tex]

Divide both sides of the equation by log(3):
[tex]6x=2x-6 \\ 6x-2x = -6 \\ 4x = -3 \\ x = - \frac{4}{3} [/tex]

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