Answer:
[tex]\frac{4}{3x-4}[/tex]
Step-by-step explanation:
The first thing we do to solve this is factor is completley
You can factor out a 4 from the numerator and get
4(3x+4)
The denominator is a difference of squares which means that
(x^2-y^2)=(x-y)(x+y)
which means that 9x^2-16=
(3x-4)(3x+4)
Put these together and get
[tex]\frac{4(3x+4)}{(3x-4)*(3x+4)}[/tex]
The 3x+4 cancels out and we get left with
[tex]\frac{4}{3x-4}[/tex]
