Answer:
[tex]m=1,182.8g[/tex]
Explanation:
Hello!
In this case, since the relationship between molecules and mass is first analyzed via the Avogadro's number to compute the moles in the given molecules:
[tex]mol=4.63x10^{24}molec*\frac{1mol}{6.022x10^{23}molec}=7.69mol[/tex]
We now use the molar mass of carbon tetrachloride (153.81 g/mol) to obtain the required grams:
[tex]m=7.69mol*\frac{153.81g}{1mol} \\\\m=1,182.8g[/tex]
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