Which inequality models the problem?

The length of a rectangle is twice its width. The perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?

2(2w) + 2(w) < 50
2w < 50
2 + 2w < 50
2w x 2 < 50

Respuesta :

l is 2w
l=2w

p is less than 50
P<50

so

P=2L+2W

2L+2W<50
2(2w)+2(w)<50

first one

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