Answer:
0.98 M
Explanation:
Given data:
Mass of sugar = 20 g
Mass of water = 59 g
Concentration of solution = ?
Solution:
1 g = 0.01 L
59 g× 0.01 L/1 g
0.059 L
Concentration formula:
C = m/v
m = moles of solute
v = volume of solution
Number of moles of sugar:
Number of moles = mass/molar mass
Number of moles = 20 g/ 342.3 g/mol
Number of moles = 0.058 mol
Now we will calculate the concentration:
C = 0.058 mol/0.059 L
C = 0.98 mol/L
C = 0.98 M
