Answer:
(2+3i)(1-2i) = (8-i)
Step-by-step explanation:
The given complex number is :
Z = (2+3i)(1-2i)
We need to find the product of the complex number
[tex]Z=2(1)+2(-2i)+3i(1)-6i^2\\\\=2-4i+3i-6i^2[/tex]
We know that, [tex]i^2=-1[/tex]
[tex]Z=2-i-6(-1)\\\\=2-i+6\\\\=8-i[/tex]
Hence, the product of the complex number is (8-i).
