contestada

A sample of air at 58.6 kPa is expanded from 250 mL to 655 mL. If thetemperature remains constant, what is the final pressure in kPa?

Respuesta :

Stephen46

Answer:

22.366 kPa

Explanation:

The final pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the final pressure

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

From the question

58.6 kPa = 58600 Pa

We have

[tex]P_2 = \frac{58600 \times 250}{655} = \frac{14650000}{655} \\ = 22366.4122... \\ = 22366[/tex]

We have the final answer as

22.366 kPa

Hope this helps you