bat81 bat81
  • 25-10-2020
  • Mathematics
contestada

I need help please
Thanks

I need help please Thanks class=

Respuesta :

felixkings
felixkings felixkings
  • 25-10-2020

Answer:

[tex]the \: formulea \: is \: : \\ y = \frac{20x {}^{3} }{ {h}^{2} } [/tex]

[tex]x = \sqrt[3]{\frac{yh {}^{2} }{20} } = \sqrt[3]{\frac{67.5h \times h {}^{2} }{20} } = \frac{3h}{2} [/tex]

Step-by-step explanation:

[tex]y \: \alpha \: x {}^{3} \\ y = kx^{3} \\ k = \frac{y}{x {}^{3} } =\frac{20h}{x {}^{3} } = \frac{20h}{h {}^{3} } = \frac{20}{h {}^{2} } \\ \\ when \: y \: = 67.5h \: then \\ x = \sqrt[3]{ \frac{k}{y} } = \frac{3h}{2} [/tex]

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