Answer:
The distance between the points is 6.71 unit
Explanation:
Given points;
(0,-8) and (3,-2)
The distance between the points is given by;
[tex]d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]
where;
x₁ = 0, x₂ = 3
y₁ = -8, y₂ = -2
[tex]d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\\\d = \sqrt{(3-0)^2 + (-2-(-8))^2} \\\\d = \sqrt{(3^2) \ + (-2+8)^2}\\\\ d = \sqrt{3^2 +6^2 } \\\\d = \sqrt{45} \\\\d = 6.71 \ unit[/tex]
Therefore, the distance between the points is 6.71 unit
