Answer:
[tex]\frac{dy}{dx}[/tex] = 8(2x + 3)³
Step-by-step explanation:
Using the function of a function rule
Given
y = f(g(x)) , then
[tex]\frac{dy}{dx}[/tex] = f'(g(x)) × g'(x)
Given
y = [tex](2x+3)^{4}[/tex] , then
[tex]\frac{dy}{dx}[/tex] = 4(2x + 3)³ × [tex]\frac{d}{dx}[/tex] (2x + 3)
= 4(2x + 3)³ × 2
= 8(2x + 3)³
