emmaerinclark emmaerinclark

23-07-2020
Mathematics

contestada

What is the smallest value of x that satisfies the equation 8x^2 - 38x + 35 = 0? Express your answer as a decimal.

Respuesta :

temitopefasola11 temitopefasola11

23-07-2020

Answer:

1.25

Step-by-step explanation:

8x² -38x + 35 = 0

8x² - 10x - 28x + 35 = 0

2x(4x - 5)-7(4x - 5) = 0

(4x−5)(2x−7) = 0

4x - 5 = 0 or 2x - 7 = 0

x = 5/4 or x = 7/2

x = 1.25 or 3.5

Smallest value being = 1.25

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