Answer:
[tex]\huge\boxed{f^{-1}(x)=-\dfrac{1}{8}x+1}[/tex]
Step-by-step explanation:
[tex]f(x)=-8x+8\to y=-8x+8[/tex]
change x with y
[tex]x=-8y+8[/tex]
solve for y
[tex]-8y+8=x[/tex] subtract 8 from both sides
[tex]-8y+8-8=x-8[/tex]
[tex]-8y=x-8[\tex] divide both sides by (-8)
[tex]\dfrac{-8y}{-8}=\dfrac{x}{-8}-\dfrac{8}{-8}\\\\y=-\dfrac{1}{8}x+1[/tex]
