Answer: See below
Step-by-step explanation:
When you see that something is to the power of a negative number, it is another way of saying 1 over.
[tex](2x-2)^-^3=\frac{1}{(2x-2)^3} =\frac{1}{(2x-2)(4x^2-8x+4)} =\frac{1}{8x^3-8x^2+8x-8}[/tex]
