Answer:
a) 11
b) 16
c) between 5 and 6
d) 16
Step-by-step explanation:
[tex]\text{a. }\quad\sqrt{121}=\sqrt{11^2}=\boxed{11}\\\\\text{b. }\quad 8\sqrt{4}=8\sqrt{2^2}=8\cdot 2=\boxed{16}\\\\\text{c. }\quad\sqrt{35}\ \dots\ \sqrt{25}<\sqrt{35}<\sqrt{36}\\\\\text{ }\qquad\sqrt{5^2}<\sqrt{35}<\sqrt{6^2}\\\\\text{ }\qquad \boxed{5<\sqrt{35}<6}\\\\\text{d. }\quad\dfrac{.8}{.05}=\dfrac{0.80\cdot 20}{.05\cdot 20}=\dfrac{16}{1}=\boxed{16}[/tex]
