Respuesta :

Answer:

Heat loss is -7871.5J

Explanation:

Mass = 692g

Initial temperature (T1) = 176°C

Final temperature (T2) = 85°C

Specific heat capacity of Al = 0.125J/g°C

Heat energy = ?

Q = mc∇t

Q = heat energy

M = mass of substance

C = specific heat capacity of substance

∇t = change in temperature of substance = T2 - T1

Q = mc∇t

Q = 692 × 0.125 × (85 - 176)

Q = 86.5 × -91

Q = -7871.5J

The heat loss is -7871.5J or -7.87kJ

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