bigsis2kaden bigsis2kaden
  • 25-08-2016
  • Mathematics
contestada

tan(x)+tan(y)=sin(x+y)/cos(x)cos(y)

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Panoyin
Panoyin Panoyin
  • 26-08-2016
[tex]tan(x) + tan(y) = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
[tex]\frac{sin(x)}{cos(x)} + \frac{sin(y)}{cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
[tex]\frac{sin(x)cos(y)}{cos(x)cos(y)} + \frac{sin(y)cos(x)}{cos(x)cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
[tex]\frac{sin(x)cos(y) + sin(y)cos(x)}{cos(x)cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
[tex]\frac{sin(x + y)}{cos(x)cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
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