Respuesta :

chudung1976

Answer:

[tex]\frac{c.sinA}{sinC} =\frac{3.sin63^{0} }{sin49^{0} } =3.542[/tex]

Step-by-step explanation:

+ We use this theorem: a/sinA=c/sinC for a triangle.

+ Then \frac{c.sinA}{sinC} =\frac{3.sin63^{0} }{sin49^{0} } =3.542

Hope you understand.