Answer:
Step-by-step explanation:
t1 = 2= 2 * 4 ^ 1 -1
t2 = 8= 2* 4^2-1
t3 = 32= 2 * 4^3 -1
t4 = 128 = 2* 4^ 4 -1
----------------------------
tn = 2 * 4^ (n - 1)
Now
the 6th term of the sequence is
t6 = 2 * 4^ 6 -1
= 2 * 1024
= 2048
hope it was helpful.
