A charge of 9.0 x 10-5C is placed in an electric field with a strength of 4.0 x 104 N. What is the electrical force acting
on the charge?

Respuesta :

Answer:

3.6 N

Explanation:

E=F/q

so

F=qxE

F= 9x10^-5x4x10^4

F= 3.6 N