fabfly4mehanni4e fabfly4mehanni4e

21-07-2016
Mathematics

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A 0.5 kg block is moving at constant speed on a horizontal surface. the friction force acting on the block is 20N, calculate uk

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meerkat18 meerkat18

21-07-2016

The friction force is equal to the normal force by the object equal to the weight of the object multiplied by the coefficient of friction. In this case, we substitute to the equation
4.9 N * 9.8 m/s2 = 20 N * ukuk is equal then to 0.245.

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